..0…*0**��pbfsT��v��lks��svPvbfs��pbfsT��v��lks��svPvcfsD2s*****D2sTcfsT��v��lks��svPvcfsD2s) www.selleckchem.com/products/MDV3100.html (74) ��1211 can be written as ��1211=��2T��1��2+��1 (75) ��1212 can be written as ��1212=(0…CsTcfsT��v��lks��svPvcfsD1s��1…CsTcfsT��v��lks��svPvcfsD1s��p0*afsT��v��lks��svPvafs-��v��lks��svPs��v��lks��svPvbfs��1+afsT��v��lks��svPvcfsD1s��1…��v��lks��svPvbfs��p+afsT��v��lks��svPvcfsD1s��p0**��1bfsT��v��lks��svPvcfsD1s000***………

****��pbfsT��v��lks��svPvcfsD1s0*****0) (76) According to 2ab��a2+b2 , we can get ��1bfsT��v��lks��svPvcfsD1s��12[��1bfsT��v��lks��svPvbfs+��1D1sTcfsT��v��lks��svPvcfsD1s]��pbfsT��v��lks��svPvcfsD1s��12[��pbfsT��v��lks��svPvbfs+��pD1sTcfsT��v��lks��svPvcfsD1s] (77) Suppose that (N11-��v��luks��svPv*N21)��0 (78) According to (xT(k)CsTcfsTxT(k-��1)��1D1sTcfsT)(N11-��v��luks��svPv*N21)(cfsCsx(k)cfsD1s��1x(k-��1))��0 N11cfsCsx(k)+xT(k-��1)��1D1sTcfsTN21��1cfsD1sx(k-��1)?(79) 2xT(k)CsTcfsT(��v��luks��svPv)cfsD1s��1x(k-��1)��xT(k)CsTcfsT, (80) (N1p-��v��luks��svPv*N2p)��0 (81) (xT(k)CsTcfsTxT(k-��p)��pD1sTcfsT)(N1p-��v��luks��svPv*N2p)(cfsCsx(k)cfsD1s��px(k-��1))��0 N1pcfsCsx(k)+xT(k-��p)��pD1sTcfsTN2p��pcfsD1sx(k-��p)?(82) 2xT(k)CsTcfsT(��v��luks��svPv)cfsD1s��px(k-��p)��xT(k)CsTcfsT, (83) Suppose (N1p-��v��luks��svPv*N2p)��0 (84) (xT��(k)afsTxT(k-��1)��1D1sTcfsT)(N11-��v��luks��svPv*N21)(afsx��(k)cfsD1s��1x(k-��1))��0(xT��(k)afsTxT(k-��p)��pD1sTcfsT)(N1p-��v��luks��svPv*N2p)(afsx��(k)cfsD1s��px(k-��p))��0 N1pafsx��(k)+xT(k-��p)��pD1sTcfsTN2p��pcfsD1sx(k-��p)?(85) 2xT��(k)afsT(��v��luks��svPv)cfsD1s��px(k-��p)��xT��(k)afsT, (86) (CsTcfsT(N11+…

N1p)cfsCs……0*afsT(N11+…N1p)afs+afsT��v��lks��svPvafs-��v��lks��svPs��v��lks��svPvbfs��1…��v��lks��svPvbfs��p0**2��1D1sTcfsTN21��1cfsD1s000***………****2��pD1sTcfsTN2p��pcfsD1s0*****0) (87) ��1221 can be written as ��1221=��3T��2��3+��2 (88) Where ��1222,��3T,��2,��2 are the same as the terms in Theorem 1. The forward difference of V2 can be written in the form of ��V2��[��i=1pxT(k)(��v��lks��?svSv)x(k)+��i=1pxT(k)(��v��luks��?svSv)x(k)]?[��i=1pxT(k?��i)(��v��lks��?svSv)x(k?��i)+��i=1pxT(k?��i)(��v��luks��?svSv)x(k?��i)]+[��i=1pxT��(k)(��v��lks��?svSv)x��(k)+��i=1pxT��(k)(��v��luks��?svSv)x��(k)]?=��w?T?2w��w=��w?T(?21+?22)��w GSK-3 (89) Where ��21,��22 are the same as the terms in Theorem 1. The forward differential of V3 can be expressed in the form of ��V3=��V31+��V32 ��V31,��V32 can be written as ��V31=��V311+��V312,��V32=��V321+��V322.